37.49.72.8 am 18. September 2019 um 17:18 Uhr

2019-09-18T17:18:25Z

37.49.72.8: Die Seite wurde neu angelegt: „== Merge Materials ==

 The following script extends from the already linked answer in that it removes any double-materials and assigns the 'correct' mate…“

2019-09-18T17:18:05Z

Die Seite wurde neu angelegt: „== Merge Materials == <pre> The following script extends from the already linked answer in that it removes any double-materials and assigns the 'correct' mate…“

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== Merge Materials ==

<pre>
The following script extends from the already linked answer in that it removes any double-materials and assigns the 'correct' materials to the faces respectively. However, you'll need to understand that a few assumptions are made here:

your original material is named something
the duplicates are named something.045, something.046 and so on
they are REALLY duplicates
you've saved your scene before you run this :)
the active object in your scene is the mesh object you want to clean
Copy the following Python code to a text editor within your file and run it:

import bpy

# only search on own object materials
mat_list = [x.material.name for x in bpy.context.object.material_slots]
remove_slots = []

# the following only works in object mode
bpy.ops.object.mode_set(mode='OBJECT')

for s in bpy.context.object.material_slots:
if s.material.name[-3:].isnumeric():
# the last 3 characters are numbers
# that indicates it might be a duplicate of another material
# but this is pure guesswork, so expect errors to happen!
if s.material.name[:-4] in mat_list:

# there is a material without the numeric extension so use it
# this again is just guessing that we're having identical node trees here

# get the material index of the 'clean' material
index_clean = mat_list.index(s.material.name[:-4])
index_wrong = mat_list.index(s.material.name)
print(index_wrong, index_clean)

# get the faces which are assigned to the 'wrong' material
faces = [x for x in bpy.context.object.data.polygons if x.material_index == index_wrong]

for f in faces:
f.material_index = index_clean

remove_slots.append(s.name)

# now remove all empty material slots:
for s in remove_slots:

if s in [x.name for x in bpy.context.object.material_slots]:
print('removing slot %s' % s)
bpy.context.object.active_material_index = [x.material.name for x in bpy.context.object.material_slots].index(s)
bpy.ops.object.material_slot_remove()
It should turn this:

start

into this:

finish

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</pre>

Blender Scripting - Versionsgeschichte

37.49.72.8 am 18. September 2019 um 17:18 Uhr

37.49.72.8: Die Seite wurde neu angelegt: „== Merge Materials ==
The following script extends from the already linked answer in that it removes any double-materials and assigns the 'correct' mate…“

@@ Zeile 1: / Zeile 1: @@
 == Merge Materials ==
+ https://blender.stackexchange.com/questions/75790/how-to-merge-around-300-duplicate-materials
 <pre>
 The following script extends from the already linked answer in that it removes any double-materials and assigns the 'correct' materials to the faces respectively. However, you'll need to understand that a few assumptions are made here: